As shown in the diagram, after refraction, the beam converges at i.e., the focus point, and then diverges after .
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We know, intensity Where, is the distance from the source (Here, focus.)
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As the person moves towards the focus, decreases and hence intensity increases.
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When the person moves away from , distance increases and hence intensity increases.
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So, the intensity first increases till , and then it will decrease.
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\n"},"encodingFormat":"text/html","position":3,"text":"first increases then decreases."},"comment":{"@type":"Comment","text":"For the given question, we have to discuss the behavior of rays after reflection from the converging lens. So we will draw a diagram with the parallel incident on a converging lens and then rays passing through it using laws of refraction. This will give us the idea of aperture variation. Intensity is inversely proportional to the aperture area."},"eduQuestionType":"Multiple choice","encodingFormat":"text/markdown","learningResourceType":"Practice problem","suggestedAnswer":[{"@type":"Answer","comment":{"@type":"Comment","text":"It is a wrong option."},"encodingFormat":"text/html","position":0,"text":"remains constant."},{"@type":"Answer","comment":{"@type":"Comment","text":"It is a wrong option."},"encodingFormat":"text/html","position":1,"text":"continuously increases."},{"@type":"Answer","comment":{"@type":"Comment","text":"It is a wrong option."},"encodingFormat":"text/html","position":2,"text":"continuously decreases."}],"text":"A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side on its principal axis, the intensity of the light"},"name":"Quiz on Geometrical Optics","typicalAgeRange":"10-17","url":"https://www.embibe.com/questions/A-parallel-beam-of-light-is-incident-on-a-converging-lens-parallel-to-its-principal-axis.-As-one-moves-away-from-the-lens-on-the-other-side-on-its-principal-axis%2C-the-intensity-of-the-light/EM4588973"}
H C Verma Solutions for Chapter: Geometrical Optics, Exercise 2: OBJECTIVE I
Author:H C Verma
H C Verma Physics Solutions for Exercise - H C Verma Solutions for Chapter: Geometrical Optics, Exercise 2: OBJECTIVE I
Attempt the practice questions on Chapter 18: Geometrical Optics, Exercise 2: OBJECTIVE I with hints and solutions to strengthen your understanding. CONCEPTS OF PHYSICS [VOLUME 1] solutions are prepared by Experienced Embibe Experts.
Questions from H C Verma Solutions for Chapter: Geometrical Optics, Exercise 2: OBJECTIVE I with Hints & Solutions
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side on its principal axis, the intensity of the light
A symmetric double convex lens is cut into two equal parts by a plane perpendicular to the principal axis. If the power of the original lens was , the power of a cut lens will be
A symmetric double convex lens is cut in two equal parts by a plane containing the principal axis. If the power of the original lens was , the power of a divided lens will be
Two concave lenses and are kept in contact with each other. If the space between the two lenses is filled with a material of smaller refractive index, the magnitude of the focal length of the combination
A point object is placed on the principal axis of a convex lens of focal length at a distance of to the left of it. The diameter of the lens is . An eye is placed to right of the lens and a distance below the principal axis. The maximum value of to see the image is